ajax提交到java后台之后处理数据的实现
2017-05-31 1247
环境：eclipse+struts
要实现的效果：点击按钮提交数据到后台之后回到前台显示出来数据
index.jsp
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 | <%@ page language="java" contentType="text/html; charset=UTF-8" pageEncoding="UTF-8"%> <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> <title>Insert title here</title> </head> <body> <input type="text" id="userinput"> <input type="button" id="submit"> <div id="msg"></div> </body> <script type="text/javascript" src="jquery-2.1.0.js"></script> <script type="text/javascript"> window.onload = function() { document.getElementById("submit").onclick = test; } function test(){ var userinput = document.getElementById("userinput"); $.post("http://localhost:8080/TestSpring/TestAction",{username:userinput.value}, function(data, textStatus){ document.getElementById("msg").innerHTML = data; }); } </script> </html> |
struts.xml
1 2 3 | <action name="TestAction" class="com.action.Test"> <result>index.jsp</result> </action> |
Test.java
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 | package com.action; import java.io.PrintWriter; import java.util.Map; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import org.apache.struts2.ServletActionContext; import com.opensymphony.xwork2.ActionContext; import com.opensymphony.xwork2.ActionSupport; public class Test extends ActionSupport { @Override public String execute() throws Exception { // TODO Auto-generated method stub HttpServletRequest request = org.apache.struts2.ServletActionContext.getRequest(); HttpServletResponse response = ServletActionContext.getResponse(); request.setCharacterEncoding("utf-8"); response.setCharacterEncoding("utf-8"); PrintWriter out = response.getWriter(); out.write(request.getParameter("username")); out.flush(); out.close(); return SUCCESS; } } |
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